What Is 143 Divisible By

In Mathematics, factors of 143 are the real numbers that evenly dissever the original number. 143 is a blended number, since it has more than two factors. We can find these factors easily by dividing 143 by the natural numbers. For example, if 45 divided by 9 is 5, then 9 is the cistron of 45.

Now, allow u.s.a. observe the factors, prime number factors and pair factors of 143 in this article.

Factors of 143

How to Find Factors of 143?

Factors are the integers that divide the original number (in this case, 143) evenly or equally.

By dividing 143 by the sequence of natural numbers, we can find the required factors. If the quotient produced afterwards segmentation, is a whole number, so the divisor is the factor.

143 ÷ i = 143

143 ÷ 11 = 13

143 ÷ 13 = xi

143 ÷ 143 = 1

Thus, the factors of 143 are i, eleven, 13 and 143.

Pair Factors of 143

Pair factors are those numbers in pairs that result in the original number (in this case, 143) when multiplied together.

1 × 143 = 143

11 × 13 = 143

Therefore, the pair factors are (1, 143) and (11, thirteen).

At present, if we consider the negative pair factors, so;

-i × -143 = 143

-11 × -13 = 143

Therefore, the negative pair factors are (-one, -143) and (-11, -13).

Prime Factorisation of 143

Prime number factors of 143 divide the original number into equal parts. The listing of prime numbers from 1 to 150 is given beneath. So, here we demand to find such prime numbers that can divide 143 completely.

List of prime numbers (1 to 150) :

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149

Step i: Since 143 is an odd number, so we cannot split up it by two. Now 143 is directly divisible by 11.

143/xi = 13

Stride two: Now thirteen is itself a prime number. Thus,

13/13 = 1

Therefore,

Prime factorisation of 143 = 11 10 13

Solved Examples

Q.1: If 11 tennis balls are bought for Rs.143. Then what is the cost of each tennis ball?

Solution: Given,

Number of assurance bought = 11

Toll of 11 assurance = Rs.143

Each ball will cost = 143/11 = xiii

Therefore, cost of each brawl is Rs.thirteen.

Q.2: Notice the sum of all the factors of i hundred and twoscore-iii.

Solution: The factors of 143 are one, 11 ,thirteen and 143.

Sum = ane + 11 + 13 + 143 = 168

Therefore, 168 is the required sum.

Q.3: What is the greatest common cistron of 145 and 143?

Respond: Let united states write the factors of both numbers.

143 → i, eleven, xiii, 143

145 → 1, 5, 29, 145

Hence, the greatest common cistron is only 1.

Q.four: What is the GCF of 143 and 156?

Solution: We know the factors of 143 are 1, 11, 13 and 143.

Factors of 156 = 1, 2, 3, 4, 6, 12, thirteen, 26, 39, 52, 78, 156

If nosotros compare the factors, 13 is the greatest mutual factor of 143 and 156.

GCF (143, 156) = thirteen

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Frequently Asked Questions on Factors of 143

1. What are the factors of 143?

Answer: At that place are a full of iv factors of 143. These factors are 1, xi,13 and 143.

2. What are the multiples of 143?

Respond: The first 10 multiples of 143 are 143, 286, 429, 572, 715, 858, 1001, 1144, 1287 and 1430.

iii. How is 143 represented as the product of prime factors?

Answer: The prime number factorisation of 143 is:

143 = 11 ten thirteen

4. Is five a cistron of 143?

Answer: No, 5 is not a gene of 143. 5 cannot divide 143 evenly.

five. Is 143 a blended number?

Answer: Yep, 143 is a composite number because it has more than 2 factors.

vi. Is 143 a perfect foursquare?

Answer: 143 is not a perfect foursquare because the root of 143 will result in a fraction.

√143 = 11.96 (approximately)